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## Суурь геометр

### Unit 7: Lesson 3

Pythagorean theorem and distance between points

# Finding distance with Pythagorean theorem

Sal finds the distance between two points with the Pythagorean theorem.

## Video transcript

- We are asked what is the distance between the following points. Pause this video and see if you can figure it out. There's multiple ways to think about it. The way I think about it is really to try to draw a right triangle where these points, where the line that connects these points is the hypotenuse and then we can just use the Pythagorean Theorem. Let me show you what I am talking about. Let me draw a right triangle, here. That is the height of my right triangle and this is the width of my right triangle. Then the hypotenuse will connect these two points. I could use my little ruler tool here to connect that point and that point right over there. I'll color it in orange. There you have it. There you have it. I have a right triangle where the line that connects those two points is the hypotenuse of that right triangle. Why is that useful? From this, can you pause the video and figure out the length of that orange line, which is the distance between those two points? What is the length of this red line? You could see it on this grid, here. This is equal to two. It's exactly two spaces, and you could even think about it in terms of coordinates. The coordinate of this point up here is negative five comma eight. Negative five comma eight. The coordinate here is X is four, Y is six. Four comma six, and so the coordinate over here is going to have the same Y coordinate as this point. This is going to be comma six. It's going to have the same X coordinate as this point. This is going to be negative five comma six. Notice, you're only changing in the Y direction and you're changing by two. What's the length of this line? You could count it out, one, two, three, four, five, six, seven, eight, nine. It's nine, or you could even say hey look, we're only changing in the X value. We're going from negative five, X equals negative five, to X equals four. We're going to increase by nine. All of that just sets us up so that we can use the Pythagorean Theorem. If we call this C, we know that A squared plus B squared is equal to C squared, or we could say that two squared ... Let me do it over here. Use that same red color. Two squared plus nine squared, plus nine squared, is going to be equal to our hypotenuse square, which I'm just calling C, is going to be equal to C squared, which is really the distance. That's what we're trying to figure out. Two squared, that is four, plus nine squared is 81. That's going to be equal to C squared. We get C squared is equal to 85. C squared is equal to 85 or C is equal to the principal root of 85. Can I simplify that a little bit? Let's see. How many times does five go into 85? It goes, let's see, it goes 17 times. Neither of those are perfect squares. Yeah, that's 50 plus 35. Yeah, I think that's about as simple as I can write it. If you wanted to express it as a decimal, you could approximate it by putting this into a calculator and however precise you want your approximation to be. That over here, that's the length of this line, our hypotenuse and our right triangle, but more importantly for the question they're asking, the distance between those points.